(x-3)^2+(x+4)^2-(x-5)^2=17x+24

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Solution for (x-3)^2+(x+4)^2-(x-5)^2=17x+24 equation: 



(x-3)^2+(x+4)^2-(x-5)^2=17x+24

We move all terms to the left:

(x-3)^2+(x+4)^2-(x-5)^2-(17x+24)=0

We get rid of parentheses

(x-3)^2+(x+4)^2-(x-5)^2-17x-24=0

We add all the numbers together, and all the variables

-17x+(x-3)^2+(x+4)^2-(x-5)^2-24=0

We move all terms containing x to the left, all other terms to the right

-17x+(x-3)^2+(x+4)^2-(x-5)^2=24

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